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(Solution) » What is the enthalpy change, in kJ/mol, for the process below?


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What is the enthalpy change, in kJ/mol, for the process below?

 

Na+(g) + Br -(g) --> NaBr(s)

 

Enter your answer rounded to the nearest integer (e.g. -827 or 1547). Do not include units as part of your answer. (Hint: Use the Born-Haber cycle. Note carefully: The reference state for Br2 is Br2(l) not Br2(g)!)

 

Data (in kJ/mol):
Enthalpy of sublimation of Na(s): 107
Standard enthalpy of formation of Br2(g): 32
Bond dissociation energy of Br2(g): 194
Ionization energies (1st, 2nd, 3rd) of Na(g): 496; 4,512; 6,912
Ionization energies (1st, 2nd, 3rd) of Br(g): 1,140; 2,103; 3,473
First electron affinity of Br(g): -326
Standard enthalpy of formation for NaBr(s): -351


 


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(Solution) » What is the enthalpy change, in kJ/mol, for the process below?.zip

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This paper was answered on 10-Jan-2018

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